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Originally posted by Valiant Dancer

... It is more cost effective to use the Venus Sun Venus Earth path to send missions to Saturn where you don't have to carry such copious amounts of fuel into space and lift it plus the probe ...

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Originally posted by sts60

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Nasa engineers don't consider Earth's velocity in their calculations

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From the Cassini Alternate Mission and Power Study (JPL 1994), section A.1, Trajectory and Propulsion Background Information:

The spacecraft's velocity with respect to the Sun, if found by vector addition: the Earth's velocity with respect to the Sun is added to the spacecraft's asymptotic, hyperbolic departure velocity with respect to the Earth. For transfers to the outer solar system, the net effect of the Earth departure hyperbola is to increase the spacecraft's velocity with respect to the Sun above the value corresponding to the Earth's velocity. This requires that [the hyperbolic excess velocity] be pointed in the same general direction as the Earth's velocity vector. For transfers to the inner solar system, however, the spacecraft's velocity must be decreased, requiring [the hyperbolic excess velocity] to be opposed to the Earth's velocity.

From the Casini EIS supporting study, vol 3 (Earth Swingby Plan):

For a collision to occur, the Earth and spacecraft must be present within the intersection ellipse at the same time. The average probability of collision, P', is proportional to the arc distance measured along the Earth's orbit for which any part of the Earth lies within the intersection ellipse. This arc distance normalized by the heliocentric distance of the Earth is
eta = tau * abs(U) / sqrt(Ux^2 + Uz^2)
where tau is the impact radius, divided by the heliocentric distance of the Earth, abs (U) is the magnitude of the velocity of the spacecraft relative to the Earth divided by the heliocentric velocity of the Earth, Ux is the radial (Sun to Earth) component of U, and Uz is the component of U normal to the Earth orbit plane direction.

From Basics of Space Flight at http://www2.jpl.nasa.gov/basics/bsf14-1.html]:

If a spacecraft is launched from a site near Earth's equator, it can take optimum advantage of the Earth's substantial rotational speed. Sitting on the launch pad near the equator, it is already moving at a speed of over 1650 km per hour relative to Earth's center. This can be applied to the speed required to orbit the Earth (approximately 28,000 km per hour). Compared to a launch far from the equator, the equator-launched vehicle would need less propellant, or a given vehicle can launch a more massive spacecraft....

For interplanetary launches, the vehicle will have to take advantage of Earth's orbital motion as well, to accommodate the limited energy available from today's launch vehicles. In the diagram below, the launch vehicle is accelerating generally in the direction of the Earth's orbital motion (in addition to using Earth's rotational speed), which has an average velocity of approximately 100,000 km per hour along its orbital path.

The same thing is also available at http://www.au.af.mil/au/awc/awcgate/jplbasic/bsf14-1.htm, which includes a diagram labeled "Launch Using Earth's Rotation and Orbital Velocities".

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NASA swindlers do things complex to show their fake cleverness

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Originally posted by bigbrain

The force of gravity exists for your probe going at 59,250 miles per hour and exists for my probe going at 80,000 miles per hour.

And then? What do you mean?

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Originally posted by bigbrain

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Originally posted by Valiant Dancer

... It is more cost effective to use the Venus Sun Venus Earth path to send missions to Saturn where you don't have to carry such copious amounts of fuel into space and lift it plus the probe ...

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This is another biggest stupidity.

Travelling in that path "Earth > Venus > Venus > Earth" Cassini has velocity of 59,250 miles per hour and is going to Jupiter and Saturn, ok?

But the Earth has already velocity of 65,000 miles per hour.
Suppose you launch the probe in direction of Jupiter and Saturn at 20,000 miles per hour (and not at 36,000)

You can go near Jupiter at 65 + 20 = 85,000 miles per hour with lower amount of fuel SINCE THE PROBE GOES ALREADY FASTER.

NASA swindlers do things complex to show their fake cleverness

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Originally posted by bigbrain

"Absotively, GeeMack, but it still seems that bigbrain doesn't quite cognivitate the force of gravity".

The force of gravity exists for your probe going at 59,250 miles per hour and exists for my probe going at 80,000 miles per hour.

And then? What do you mean?

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Originally posted by Valiant Dancer

But your probe only exists in Fantasyland.

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Originally posted by bigbrain

"The probe does not go faster than that"

Than that????? How much?

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Originally posted by bigbrain

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Originally posted by Valiant Dancer

But your probe only exists in Fantasyland.

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YOU WENT TO THE MOON, TO MARS AND SATURN ONLY IN FANTASYLAND

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Originally posted by bigbrain

"Cassini experienced a force of about 33 Newtons towards the Sun while still in the vicinity of Earth".

Do you know how many kilograms are 33 Newtons?

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